What is the derivative of g(x)=x(x-4)^3 ?

The derivative of g(x)=x(x-4)^3 is (x-4)^3+3x(x-4)^2

What is the first derivative of g(x)=x(x-4)^3 ?

The first derivative of g(x)=x(x-4)^3 is (x-4)^3+3x(x-4)^2

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derivative of

g (x) = x (x - 4)^{3}

(x - 4)^{3} + 3 x (x - 4)^{2}

Solution steps

\frac{d}{d x} (x (x - 4)^{3})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = (x - 4)^{3}

= \frac{d x}{d x} (x - 4)^{3} + \frac{d}{d x} ((x - 4)^{3}) x

\frac{d x}{d x} = 1

\frac{d}{d x} ((x - 4)^{3}) = 3 (x - 4)^{2}

= 1 \cdot (x - 4)^{3} + 3 (x - 4)^{2} x

Simplify

= (x - 4)^{3} + 3 x (x - 4)^{2}

x \to 0 lim (\frac{7 x ^{4} - x ^{3}}{x})

\int e^{t x} d x

\int 4 e^{3 x} d x

4 y^{^{''}} - y^{^{'}} + 1 = 0

t \to \infty lim (sin (t))

What is the derivative of g(x)=x(x-4)^3 ?
The derivative of g(x)=x(x-4)^3 is (x-4)^3+3x(x-4)^2
What is the first derivative of g(x)=x(x-4)^3 ?
The first derivative of g(x)=x(x-4)^3 is (x-4)^3+3x(x-4)^2