What is the solution for f^'(x)=2x^2+x-1 ?

The solution for f^'(x)=2x^2+x-1 is f(x)=(2x^3)/3+(x^2)/2-x+c_{1}

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f^'(x)=2x^2+x-1

f^{^{'}} (x) = 2 x^{2} + x - 1

f (x) = \frac{2 x ^{3}}{3} + \frac{x ^{2}}{2} - x + c_{1}

Solution steps

f^{'} (x) = 2 x^{2} + x - 1

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int 2 x^{2} + x - 1 d x

\int 2 x^{2} + x - 1 d x = \frac{2 x ^{3}}{3} + \frac{x ^{2}}{2} - x + c_{1}

f (x) = \frac{2 x ^{3}}{3} + \frac{x ^{2}}{2} - x + c_{1}

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What is the solution for f^'(x)=2x^2+x-1 ?
The solution for f^'(x)=2x^2+x-1 is f(x)=(2x^3)/3+(x^2)/2-x+c_{1}