What is the derivative of 8x^3 ?

The derivative of 8x^3 is 24x^2

What is the first derivative of 8x^3 ?

The first derivative of 8x^3 is 24x^2

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derivative of

8 x^{3}

24 x^{2}

Solution steps

\frac{d}{d x} (8 x^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 \cdot 3 x^{3 - 1}

Simplify

= 24 x^{2}

x y^{^{'}} + 2 y = - 2 e^{x}

x \to - 3 lim (\frac{7}{x + 3})

y^{^{'}} = t^{2} - y

\frac{d}{d x} (arccos (\frac{3}{x}))

7 y^{^{''}} + 4 y^{^{'}} = 0