What is (\partial)/(\partial x)(cos(w+x)sin(y-z)) ?

The answer to (\partial)/(\partial x)(cos(w+x)sin(y-z)) is -sin(y-z)sin(w+x)

Popular >

(\partial)/(\partial x)(cos(w+x)sin(y-z))

\frac{\partial}{\partial x} (cos (w + x) sin (y - z))

- sin (y - z) sin (w + x)

Solution steps

\frac{\partial}{\partial x} (cos (w + x) sin (y - z))

Treat

w, y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (y - z) \frac{\partial}{\partial x} (cos (w + x))

Apply the chain rule:

- sin (w + x) \frac{\partial}{\partial x} (w + x)

= - sin (w + x) \frac{\partial}{\partial x} (w + x)

\frac{\partial}{\partial x} (w + x) = 1

= sin (y - z) (- sin (w + x) \cdot 1)

Simplify

= - sin (y - z) sin (w + x)

\frac{d}{d t} (3 t - 2)

\int_{0}^{1} \frac{1}{( x + 1 ) ( x + 2 )} d x

f (x) = 17 tan (x), at x = \frac{π}{4}

5 x^{4} 25 - x^{2}

f (x) = (x + 2) 2 x - 3

What is (\partial)/(\partial x)(cos(w+x)sin(y-z)) ?
The answer to (\partial)/(\partial x)(cos(w+x)sin(y-z)) is -sin(y-z)sin(w+x)