What is the limit as x approaches 5 of (x^2-9)/(x-3) ?

The limit as x approaches 5 of (x^2-9)/(x-3) is 8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 5 of (x^2-9)/(x-3)

x \to 5 lim (\frac{x ^{2} - 9}{x - 3})

8

Solution steps

x \to 5 lim (\frac{x ^{2} - 9}{x - 3})

Plug in the value

x = 5

= \frac{5 ^{2} - 9}{5 - 3}

Simplify

= 8

y^{^{'}} - 2 y = 4

sin (tan (e^{x^{2}}))

\int \frac{1}{( s ^{2} + 1 ) ^{3}} d s

y^{^{''}} - 4 y^{^{'}} + 5 y = 0, y (0) = 1, y^{^{'}} (0) = - 1

\int \frac{x ^{2}}{x ^{3} + 2} d x

What is the limit as x approaches 5 of (x^2-9)/(x-3) ?
The limit as x approaches 5 of (x^2-9)/(x-3) is 8