What is the integral of (100)/(x^2) ?

The integral of (100)/(x^2) is -(100)/x+C

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integral of (100)/(x^2)

\int \frac{100}{x ^{2}} d x

- \frac{100}{x} + C

Solution steps

\int \frac{100}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 100 \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= 100 (- \frac{1}{x})

Simplify

100 (- \frac{1}{x}) : - \frac{100}{x}

= - \frac{100}{x}

Add a constant to the solution

= - \frac{100}{x} + C

x^{2} + 3 x + 14

\int \frac{x}{8 + x ^{2}} d x

y = x, y = x^{4}, (0, 1)

n = 1 \sum \infty \frac{1}{n} - \frac{1}{n + 3}

y = 0, y = 2 x^{2}, y = 12 x - 4 x^{2}, [0, 2]