What is (\partial)/(\partial y)(x^2-3xy) ?

The answer to (\partial)/(\partial y)(x^2-3xy) is -3x

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(\partial)/(\partial y)(x^2-3xy)

\frac{\partial}{\partial y} (x^{2} - 3 x y)

- 3 x

Solution steps

\frac{\partial}{\partial y} (x^{2} - 3 x y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2}) - \frac{\partial}{\partial y} (3 x y)

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (3 x y) = 3 x

= 0 - 3 x

Simplify

= - 3 x

30 y^{^{''}} - 25 y^{^{'}} = 0

\int x e^{x} d x

\int_{0}^{1} \frac{e ^{z} + 1}{e ^{z} + z} d z

\frac{d y}{d x} = 40 - 3 y

\int x^{3} cos (x^{4} + 1) d x

What is (\partial)/(\partial y)(x^2-3xy) ?
The answer to (\partial)/(\partial y)(x^2-3xy) is -3x