What is the integral from 0 to 9 of piy^2 ?

The integral from 0 to 9 of piy^2 is pi243

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integral from 0 to 9 of piy^2

\int_{0}^{9} π y^{2} d y

π 243

Decimal Notation

763.40701 \dots

Solution steps

\int_{0}^{9} π y^{2} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{9} y^{2} d y

Apply the Power Rule

: [\frac{y ^{3}}{3}]_{0}^{9}

= π [\frac{y ^{3}}{3}]_{0}^{9}

Compute the boundaries:

243

= π 243

\frac{\partial}{\partial x} (x + \frac{1}{y})

\frac{( y ^{4} - x ^{2} ) d y}{d x} = - x y

\int \frac{9 + t + t ^{2}}{t} d t

\int sin (x) \cdot e^{c o s (x)} d x

\frac{d}{d x} (\frac{30}{x ^{4}})

What is the integral from 0 to 9 of piy^2 ?
The integral from 0 to 9 of piy^2 is pi243