What is the integral from 1 to 4 of 2/(x^3) ?

The integral from 1 to 4 of 2/(x^3) is 15/16

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integral from 1 to 4 of 2/(x^3)

\int_{1}^{4} \frac{2}{x ^{3}} d x

\frac{15}{16}

Decimal Notation

0.9375

Solution steps

\int_{1}^{4} \frac{2}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1}^{4} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{4}

= 2 [- \frac{1}{2 x ^{2}}]_{1}^{4}

Compute the boundaries:

\frac{15}{32}

= 2 \cdot \frac{15}{32}

Simplify

= \frac{15}{16}

f (x) = 5 cot (\frac{x}{8})

x \to 0 lim (x^{5} ln (x))

\frac{d}{d y} (x^{y^{2}})

\int (3 x^{2} + 10 x) (x^{3} + 5 x^{2} + 6) d x

\frac{d y}{d x} = (y - x + 1)^{2} + 1

What is the integral from 1 to 4 of 2/(x^3) ?
The integral from 1 to 4 of 2/(x^3) is 15/16