What is the derivative of y=(x+3)^3 ?

The derivative of y=(x+3)^3 is 3(x+3)^2

What is the first derivative of y=(x+3)^3 ?

The first derivative of y=(x+3)^3 is 3(x+3)^2

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derivative of

y = (x + 3)^{3}

3 (x + 3)^{2}

Solution steps

\frac{d}{d x} ((x + 3)^{3})

Apply the chain rule:

3 (x + 3)^{2} \frac{d}{d x} (x + 3)

= 3 (x + 3)^{2} \frac{d}{d x} (x + 3)

\frac{d}{d x} (x + 3) = 1

= 3 (x + 3)^{2} \cdot 1

Simplify

= 3 (x + 3)^{2}

\frac{d y}{d t} = - \frac{y}{t}

\int \frac{6}{x ^{2} - 1} d x

f (x) = 4 x^{2} sin (x) - 7 x

\int_{0}^{5} \frac{1}{3 x + 1} d x

x \to - 1 - lim (\frac{∣ x + 1 ∣}{x + 1})

What is the derivative of y=(x+3)^3 ?
The derivative of y=(x+3)^3 is 3(x+3)^2
What is the first derivative of y=(x+3)^3 ?
The first derivative of y=(x+3)^3 is 3(x+3)^2