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Popular >

y^'=x+2y

Solution

y^{^{'}} = x + 2 y

Solution

y = - \frac{2 x + 1}{4} + c_{1} e^{2 x}

Solution steps

y^{'} (x) = x + 2 y

Solve linear ODE:

y = - \frac{2 x + 1}{4} + c_{1} e^{2 x}

y = - \frac{2 x + 1}{4} + c_{1} e^{2 x}

Graph

Popular Examples

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y = \frac{4}{- 4 x + 3 + 3 x ^{2}} \frac{d y}{d x}

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n = 0 \sum \infty n! (2 x - 1)^{n}

(\partial)/(\partial x)(4x+3y)

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Frequently Asked Questions (FAQ)

What is the solution for y^'=x+2y ?
The solution for y^'=x+2y is y=-(2x+1)/4+c_{1}e^{2x}