What is the solution for (x^2-yx^2)dy+y^2(1+x)dx=0 ?

The solution for (x^2-yx^2)dy+y^2(1+x)dx=0 is y=-1/(\W(-(1){e^{\frac{c_{1}x-1)/x}x})}

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(x^2-yx^2)dy+y^2(1+x)dx=0

(x^{2} - y x^{2}) d y + y^{2} (1 + x) d x = 0

y = - \frac{1}{W ( - \frac{1}{e ^{\frac{c _{1} x - 1}{x}} x} )}

Solution steps

(x^{2} - y x^{2}) d y + y^{2} (1 + x) d x = 0

Solve separable ODE:

y = - \frac{1}{W ( - \frac{1}{e ^{\frac{c _{1} x - 1}{x}} x} )}

y = - \frac{1}{W ( - \frac{1}{e ^{\frac{c _{1} x - 1}{x}} x} )}

\frac{\partial}{\partial t} (x + y sin (t))

\int t^{2} - 9 d t

\int (3 x^{2} + 4 x + 2) d x

\frac{d}{d x} (\frac{48}{( 1 - 2 x ) ^{4}})

\frac{d}{d x} (ln (x + 2 + x^{2}))

What is the solution for (x^2-yx^2)dy+y^2(1+x)dx=0 ?
The solution for (x^2-yx^2)dy+y^2(1+x)dx=0 is y=-1/(\W(-(1){e^{\frac{c_{1}x-1)/x}x})}