What is area y=sqrt(x),y=x^2,x=2 ?

The answer to area y=sqrt(x),y=x^2,x=2 is (10-4sqrt(2))/3

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area y=sqrt(x),y=x^2,x=2

area

y = x, y = x^{2}, x = 2

\frac{10 - 4 2}{3}

Decimal Notation

1.44771 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} x - x^{2} d x

Solve

\int_{0}^{2} x - x^{2} d x : \frac{10 - 4 2}{3}

The area is:

= \frac{10 - 4 2}{3}

f (t) = t^{3}

\frac{q x + r}{s x + t}

\frac{d}{d x} (ln (x) - sin (x))

\frac{x ^{3} + 6 x}{3}

g (x) = 3 x - 2 + \frac{1}{x} - \frac{1}{x ^{2}}

What is area y=sqrt(x),y=x^2,x=2 ?
The answer to area y=sqrt(x),y=x^2,x=2 is (10-4sqrt(2))/3