What is the sum from n=0 to infinity of 1/(3^n+2) ?

The sum from n=0 to infinity of 1/(3^n+2) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of 1/(3^n+2)

n = 0 \sum \infty \frac{1}{3 ^{n} + 2}

converges

Solution steps

n = 0 \sum \infty \frac{1}{3 ^{n} + 2}

Apply Series Ratio Test:

converges

= converges

\int θ cos (θ) d θ

\int \frac{x ^{4}}{1 - x ^{2}} d x

\int x^{2} x^{3} d x

\int 7 v (v^{2} + 6)^{2} d v

6 x - x^{3}, ∣ 2 \cdot x ∣

What is the sum from n=0 to infinity of 1/(3^n+2) ?
The sum from n=0 to infinity of 1/(3^n+2) is converges