What is the derivative of ln(16+x^2) ?

The derivative of ln(16+x^2) is (2x)/(16+x^2)

What is the first derivative of ln(16+x^2) ?

The first derivative of ln(16+x^2) is (2x)/(16+x^2)

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derivative of

ln (16 + x^{2})

\frac{2 x}{16 + x ^{2}}

Solution steps

\frac{d}{d x} (ln (16 + x^{2}))

Apply the chain rule:

\frac{1}{16 + x ^{2}} \frac{d}{d x} (16 + x^{2})

= \frac{1}{16 + x ^{2}} \frac{d}{d x} (16 + x^{2})

\frac{d}{d x} (16 + x^{2}) = 2 x

= \frac{1}{16 + x ^{2}} \cdot 2 x

Simplify

\frac{1}{16 + x ^{2}} \cdot 2 x : \frac{2 x}{16 + x ^{2}}

= \frac{2 x}{16 + x ^{2}}

v \to 1 lim (\frac{v ^{2} - 5}{v})

x \to \infty + lim (3 \cdot + 2^{x})

\frac{x}{( x + 1 )}

\int (x^{2} + 4)^{\frac{1}{2}} d x

What is the derivative of ln(16+x^2) ?
The derivative of ln(16+x^2) is (2x)/(16+x^2)
What is the first derivative of ln(16+x^2) ?
The first derivative of ln(16+x^2) is (2x)/(16+x^2)