What is the integral from 0 to 2 of (8ti-t^3j+4t^7k) ?

The integral from 0 to 2 of (8ti-t^3j+4t^7k) is 16i-j*4+128k

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integral from 0 to 2 of (8ti-t^3j+4t^7k)

\int_{0}^{2} (8 t i - t^{3} j + 4 t^{7} k) d t

16 i - j \cdot 4 + 128 k

Solution steps

\int_{0}^{2} 8 t i - t^{3} j + 4 t^{7} k d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 8 t i d t - \int_{0}^{2} t^{3} j d t + \int_{0}^{2} 4 t^{7} k d t

\int_{0}^{2} 8 t i d t = 16 i

\int_{0}^{2} t^{3} j d t = j \cdot 4

\int_{0}^{2} 4 t^{7} k d t = 128 k

= 16 i - j \cdot 4 + 128 k

x \to 3 - lim (6 - x)

d y = \frac{d x}{y}

\int cot^{5} (\frac{x}{2}) csc^{2} (\frac{x}{2}) d x

sin^{2} (9 x)

y = 28 - x^{2}, y = 0.6 x, y = 3 x

What is the integral from 0 to 2 of (8ti-t^3j+4t^7k) ?
The integral from 0 to 2 of (8ti-t^3j+4t^7k) is 16i-j*4+128k