What is the derivative of 1/(2sqrt(r))+1/(9r^{(8/9))} ?

The derivative of 1/(2sqrt(r))+1/(9r^{(8/9))} is -1/(4r^{3/2)}-8/(81r^{17/9)}

What is the first derivative of 1/(2sqrt(r))+1/(9r^{(8/9))} ?

The first derivative of 1/(2sqrt(r))+1/(9r^{(8/9))} is -1/(4r^{3/2)}-8/(81r^{17/9)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{1}{2 r} + \frac{1}{9 r ^{(\frac{8}{9})}}

- \frac{1}{4 r ^{\frac{3}{2}}} - \frac{8}{81 r ^{\frac{17}{9}}}

Solution steps

\frac{d}{d r} (\frac{1}{2 r} + \frac{1}{9 r ^{\frac{8}{9}}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d r} (\frac{1}{2 r}) + \frac{d}{d r} (\frac{1}{9 r ^{\frac{8}{9}}})

\frac{d}{d r} (\frac{1}{2 r}) = - \frac{1}{4 r ^{\frac{3}{2}}}

\frac{d}{d r} (\frac{1}{9 r ^{\frac{8}{9}}}) = - \frac{8}{81 r ^{\frac{17}{9}}}

= - \frac{1}{4 r ^{\frac{3}{2}}} - \frac{8}{81 r ^{\frac{17}{9}}}

x \to 0 lim (\frac{1}{3 x ^{3}})

y^{^{''}} - 2 y^{^{'}} + y = t^{3} e^{t}

\frac{d}{d x} (4 x^{2} cos (3 x))

y^{^{''}} - 4 y^{^{'}} + 4 y = x e^{2 x}

\frac{d}{d x} ((1 + x + x^{2})^{99})

What is the derivative of 1/(2sqrt(r))+1/(9r^{(8/9))} ?
The derivative of 1/(2sqrt(r))+1/(9r^{(8/9))} is -1/(4r^{3/2)}-8/(81r^{17/9)}
What is the first derivative of 1/(2sqrt(r))+1/(9r^{(8/9))} ?
The first derivative of 1/(2sqrt(r))+1/(9r^{(8/9))} is -1/(4r^{3/2)}-8/(81r^{17/9)}