What is the derivative of (7x+4^2) ?

The derivative of (7x+4^2) is 14(7x+4)

What is the first derivative of (7x+4^2) ?

The first derivative of (7x+4^2) is 14(7x+4)

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\frac{d}{d x} ((7 x + 4)^{2})

14 (7 x + 4)

Solution steps

\frac{d}{d x} ((7 x + 4)^{2})

Apply the chain rule:

2 (7 x + 4) \frac{d}{d x} (7 x + 4)

= 2 (7 x + 4) \frac{d}{d x} (7 x + 4)

\frac{d}{d x} (7 x + 4) = 7

= 2 (7 x + 4) \cdot 7

Simplify

= 14 (7 x + 4)

\int \frac{7}{x 4 - 49 ln ^{2} ( x )} d x

\int 3 x (5 - x) d x

y^{^{''}} + 9 y = tan (3 x)

\int \frac{1}{12 x - 9 x ^{2}} d x

x \to 0 lim (\frac{x ^{2} + 3 x}{x})

What is the derivative of (7x+4^2) ?
The derivative of (7x+4^2) is 14(7x+4)
What is the first derivative of (7x+4^2) ?
The first derivative of (7x+4^2) is 14(7x+4)