What is the tangent of-x^3-5x^2+3x-1 ?

The tangent of-x^3-5x^2+3x-1 is y=(-3a_{0}^2-10a_{0}+3)x+2a_{0}^3+5a_{0}^2-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of-x^3-5x^2+3x-1

tangent of

- x^{3} - 5 x^{2} + 3 x - 1

y = (- 3 a_{0}^{2} - 10 a_{0} + 3) x + 2 a_{0}^{3} + 5 a_{0}^{2} - 1

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - a_{0}^{3} - 5 a_{0}^{2} + 3 a_{0} - 1)

Find the slope of

y = - x^{3} - 5 x^{2} + 3 x - 1 : \frac{d y}{d x} = - 3 x^{2} - 10 x + 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 3 a_{0}^{2} - 10 a_{0} + 3

Find the line with slope m=

- 3 a_{0}^{2} - 10 a_{0} + 3

and passing through

(a_{0}, - a_{0}^{3} - 5 a_{0}^{2} + 3 a_{0} - 1) : y = (- 3 a_{0}^{2} - 10 a_{0} + 3) x + 2 a_{0}^{3} + 5 a_{0}^{2} - 1

y = (- 3 a_{0}^{2} - 10 a_{0} + 3) x + 2 a_{0}^{3} + 5 a_{0}^{2} - 1

x \to 4 + lim (\frac{∣ 4 - x ∣}{4 - x})

\frac{d}{d x} (256 sin (8 x))

n = 1 \sum \infty \frac{5}{3 ^{n}}

\frac{( e ^{x} + 1 ) d y}{d x} = y - y e^{x}

y = \frac{400}{x} + 7 + \frac{1}{5} x

What is the tangent of-x^3-5x^2+3x-1 ?
The tangent of-x^3-5x^2+3x-1 is y=(-3a_{0}^2-10a_{0}+3)x+2a_{0}^3+5a_{0}^2-1