What is the derivative of f(x)=-0.004x^3-0.3x^2+600x-800 ?

The derivative of f(x)=-0.004x^3-0.3x^2+600x-800 is -0.012x^2-0.6x+600

What is the first derivative of f(x)=-0.004x^3-0.3x^2+600x-800 ?

The first derivative of f(x)=-0.004x^3-0.3x^2+600x-800 is -0.012x^2-0.6x+600

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derivative of

f (x) = - 0.004 x^{3} - 0.3 x^{2} + 600 x - 800

- 0.012 x^{2} - 0.6 x + 600

Solution steps

\frac{d}{d x} (- 0.004 x^{3} - 0.3 x^{2} + 600 x - 800)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (0.004 x^{3}) - \frac{d}{d x} (0.3 x^{2}) + \frac{d}{d x} (600 x) - \frac{d}{d x} (800)

\frac{d}{d x} (0.004 x^{3}) = 0.012 x^{2}

\frac{d}{d x} (0.3 x^{2}) = 0.6 x

\frac{d}{d x} (600 x) = 600

\frac{d}{d x} (800) = 0

= - 0.012 x^{2} - 0.6 x + 600 - 0

Simplify

= - 0.012 x^{2} - 0.6 x + 600

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What is the derivative of f(x)=-0.004x^3-0.3x^2+600x-800 ?
The derivative of f(x)=-0.004x^3-0.3x^2+600x-800 is -0.012x^2-0.6x+600
What is the first derivative of f(x)=-0.004x^3-0.3x^2+600x-800 ?
The first derivative of f(x)=-0.004x^3-0.3x^2+600x-800 is -0.012x^2-0.6x+600