What is the derivative of 4x^2-x ?

The derivative of 4x^2-x is 8x-1

What is the first derivative of 4x^2-x ?

The first derivative of 4x^2-x is 8x-1

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\frac{d}{d x} (4 x^{2} - x)

8 x - 1

Solution steps

\frac{d}{d x} (4 x^{2} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) - \frac{d x}{d x}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d x}{d x} = 1

= 8 x - 1

\int 4 x (2 x^{2} + 1)^{8} d x

f (x) = x^{2} - 5, at x = 1

x^{3}, at \frac{16}{3}

y^{^{''}} - 4 y^{^{'}} - 5 y = 0, y (1) = 0, y^{^{'}} (1) = 8

- cot (x)