What is inverse oflaplace (48)/(s^5) ?

The answer to inverse oflaplace (48)/(s^5) is 2t^4

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inverse oflaplace (48)/(s^5)

inverse laplace

\frac{48}{s ^{5}}

2 t^{4}

Solution steps

L^{- 1} {\frac{48}{s ^{5}}}

= L^{- 1} {2 \cdot \frac{24}{s ^{5}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 2 L^{- 1} {\frac{24}{s ^{5}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{( n ) !}{s ^{n + 1}}} = t^{n}

L^{- 1} {\frac{24}{s ^{5}}} = t^{4}

= 2 t^{4}

\int e^{2 x^{3} - 1} x^{2} d x

\int 3 cos^{4} (x) d x

x \to 0 lim (\frac{x ^{2} - 1}{x + 1})

\int \frac{8}{3 cos ( 2 x ) + 1} d x

x \to 2 + lim (\frac{1}{x ^{2} - 4})

What is inverse oflaplace (48)/(s^5) ?
The answer to inverse oflaplace (48)/(s^5) is 2t^4