What is derivative of f(x)=(4z^4+2z^2+1)(2z^3-z) ?

The answer to derivative of f(x)=(4z^4+2z^2+1)(2z^3-z) is (dz)/(dx)=0

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derivative of f(x)=(4z^4+2z^2+1)(2z^3-z)

derivative of

f (x) = (4 z^{4} + 2 z^{2} + 1) (2 z^{3} - z)

\frac{d z}{d x} = 0

Solution steps

f (x) = (4 z^{4} + 2 z^{2} + 1) (2 z^{3} - z)

Treat

z

z (x)

Differentiate both sides:

0 = 56 z^{6} \frac{d z}{d x} - \frac{d z}{d x}

Isolate

\frac{d z}{d x} : \frac{d z}{d x} = 0

\frac{d z}{d x} = 0

\int - \frac{1}{2 x + 1} d x

\frac{d}{d x} (- \frac{2 x}{( - 3 + x ^{2} ) ^{2}})

\int (sec^{2} (x) + x) d x

\int_{b}^{a} f (x) d x

\int \frac{x ^{3} + x + 1}{x ^{2} - x} d x

What is derivative of f(x)=(4z^4+2z^2+1)(2z^3-z) ?
The answer to derivative of f(x)=(4z^4+2z^2+1)(2z^3-z) is (dz)/(dx)=0