What is the integral from 0 to pi/3 of (sec^2(x)) ?

The integral from 0 to pi/3 of (sec^2(x)) is square root of 3

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integral from 0 to pi/3 of (sec^2(x))

\int_{0}^{\frac{π}{3}} (sec^{2} (x)) d x

3

Decimal

1.73205 \dots

Solution steps

\int_{0}^{\frac{π}{3}} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= [tan (x)]_{0}^{\frac{π}{3}}

Compute the boundaries:

3

= 3

y = sin (x cos (x))

\frac{d}{d x} (x (x - 1)^{2})

\frac{\partial}{\partial x} (\frac{4 x}{5 + y})

\frac{1}{c + k e ^{c}}

y^{^{''}} - 8 y^{^{'}} + 16 y = \frac{( 10.5 e ^{4 t} )}{( t ^{2} + 1 )}

What is the integral from 0 to pi/3 of (sec^2(x)) ?
The integral from 0 to pi/3 of (sec^2(x)) is square root of 3