What is the limit as x approaches 4 of (x^3+8)/(x+2) ?

The limit as x approaches 4 of (x^3+8)/(x+2) is 12

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limit as x approaches 4 of (x^3+8)/(x+2)

x \to 4 lim (\frac{x ^{3} + 8}{x + 2})

12

Solution steps

x \to 4 lim (\frac{x ^{3} + 8}{x + 2})

Plug in the value

x = 4

= \frac{4 ^{3} + 8}{4 + 2}

Simplify

= 12

x = - 2, x = 2, y = 5 x, y = x^{2} - 6

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\int_{- 2}^{3} \frac{6}{x ^{4}} d x

\int (x ln (2 x)) d x

What is the limit as x approaches 4 of (x^3+8)/(x+2) ?
The limit as x approaches 4 of (x^3+8)/(x+2) is 12