What is the integral from 1 to infinity of x/(x^2+3) ?

The integral from 1 to infinity of x/(x^2+3) is diverges

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integral from 1 to infinity of x/(x^2+3)

\int_{1}^{\infty} \frac{x}{x ^{2} + 3} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{x}{x ^{2} + 3} d x

Compute the indefinite integral:

\int \frac{x}{x ^{2} + 3} d x = \frac{1}{2} ln x^{2} + 3 + C

Compute the boundaries:

\int_{1}^{\infty} \frac{x}{x ^{2} + 3} d x =

diverges

= diverges

\int 1 - 16 x^{2} d x

arcsin (\frac{x}{2})

\frac{d y}{d x} = \frac{2 x}{x + 2}

\int \frac{12}{x ^{5}} d x

n \to \infty lim (e^{3 n^{2}})

What is the integral from 1 to infinity of x/(x^2+3) ?
The integral from 1 to infinity of x/(x^2+3) is diverges