What is the derivative of x^3(x-4) ?

The derivative of x^3(x-4) is 4x^3-12x^2

What is the first derivative of x^3(x-4) ?

The first derivative of x^3(x-4) is 4x^3-12x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{3} (x - 4))

4 x^{3} - 12 x^{2}

Solution steps

\frac{d}{d x} (x^{3} (x - 4))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3}, g = x - 4

= \frac{d}{d x} (x^{3}) (x - 4) + \frac{d}{d x} (x - 4) x^{3}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (x - 4) = 1

= 3 x^{2} (x - 4) + 1 \cdot x^{3}

Simplify

3 x^{2} (x - 4) + 1 \cdot x^{3} : 4 x^{3} - 12 x^{2}

= 4 x^{3} - 12 x^{2}

91 - 90 e^{- 0.2 t}

\frac{6}{s} + 16 \cdot \frac{1}{s ^{2} + 16}

f (x) = \frac{2}{4 - x}, at x = - 1

(sin^{2} (x))^{^{'}}

\frac{d}{d x} (4 x^{\frac{1}{3}})

What is the derivative of x^3(x-4) ?
The derivative of x^3(x-4) is 4x^3-12x^2
What is the first derivative of x^3(x-4) ?
The first derivative of x^3(x-4) is 4x^3-12x^2