What is the derivative of x^3-5/x+4 ?

The derivative of x^3-5/x+4 is 3x^2+5/(x^2)

What is the first derivative of x^3-5/x+4 ?

The first derivative of x^3-5/x+4 is 3x^2+5/(x^2)

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\frac{d}{d x} (x^{3} - \frac{5}{x} + 4)

3 x^{2} + \frac{5}{x ^{2}}

Solution steps

\frac{d}{d x} (x^{3} - \frac{5}{x} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (\frac{5}{x}) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (\frac{5}{x}) = - \frac{5}{x ^{2}}

\frac{d}{d x} (4) = 0

= 3 x^{2} - (- \frac{5}{x ^{2}}) + 0

Simplify

= 3 x^{2} + \frac{5}{x ^{2}}

\frac{d}{d x} (200)

x x

\frac{d}{d x} (a e^{- x})

\frac{\partial}{\partial x} (e^{6 y} sin (- 6 x))

What is the derivative of x^3-5/x+4 ?
The derivative of x^3-5/x+4 is 3x^2+5/(x^2)
What is the first derivative of x^3-5/x+4 ?
The first derivative of x^3-5/x+4 is 3x^2+5/(x^2)