What is the solution for (xdy)/(dx)=yln(xy) ?

The solution for (xdy)/(dx)=yln(xy) is y=(e^{c_{1}x-1})/x

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(xdy)/(dx)=yln(xy)

\frac{x d y}{d x} = y ln (x y)

y = \frac{e ^{c_{1} x - 1}}{x}

Solution steps

\frac{x d y}{d x} = y ln (x y)

Solve using substitution:

y = \frac{e ^{c_{1} x - 1}}{x}

y = \frac{e ^{c_{1} x - 1}}{x}

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What is the solution for (xdy)/(dx)=yln(xy) ?
The solution for (xdy)/(dx)=yln(xy) is y=(e^{c_{1}x-1})/x