What is the integral from-1 to 1 of x^2+y^2 ?

The integral from-1 to 1 of x^2+y^2 is 2y^2+2/3

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integral from-1 to 1 of x^2+y^2

\int_{- 1}^{1} x^{2} + y^{2} d x

2 y^{2} + \frac{2}{3}

Solution steps

\int_{- 1}^{1} x^{2} + y^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} y^{2} d x + \int_{- 1}^{1} x^{2} d x

\int_{- 1}^{1} y^{2} d x = 2 y^{2}

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

= 2 y^{2} + \frac{2}{3}

\int sec^{2} (x) tan^{6} (x) d x

\frac{\partial}{\partial y} (x^{2} e^{5 y})

F (s) = \frac{7}{4 s - 12}

\int \frac{1}{100 - x} d x

f (x) = \frac{6 x ^{4} - 9 x ^{2}}{3 x ^{3}}

What is the integral from-1 to 1 of x^2+y^2 ?
The integral from-1 to 1 of x^2+y^2 is 2y^2+2/3