What is the derivative of 12x^3-48x^2+48x ?

The derivative of 12x^3-48x^2+48x is 36x^2-96x+48

What is the first derivative of 12x^3-48x^2+48x ?

The first derivative of 12x^3-48x^2+48x is 36x^2-96x+48

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\frac{d}{d x} (12 x^{3} - 48 x^{2} + 48 x)

36 x^{2} - 96 x + 48

Solution steps

\frac{d}{d x} (12 x^{3} - 48 x^{2} + 48 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (12 x^{3}) - \frac{d}{d x} (48 x^{2}) + \frac{d}{d x} (48 x)

\frac{d}{d x} (12 x^{3}) = 36 x^{2}

\frac{d}{d x} (48 x^{2}) = 96 x

\frac{d}{d x} (48 x) = 48

= 36 x^{2} - 96 x + 48

\frac{1}{s ^{2} + 6 s + 13}

\int \frac{x ^{2} + 49}{x} d x

f (x) = x - 4

\frac{d}{d x} (\frac{1}{2 x ^{3}})

\frac{\partial}{\partial r} (r e^{s})

What is the derivative of 12x^3-48x^2+48x ?
The derivative of 12x^3-48x^2+48x is 36x^2-96x+48
What is the first derivative of 12x^3-48x^2+48x ?
The first derivative of 12x^3-48x^2+48x is 36x^2-96x+48