What is the limit as x approaches 0+of ln(x+1) ?

The limit as x approaches 0+of ln(x+1) is 0

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limit as x approaches 0+of ln(x+1)

x \to 0 + lim (ln (x + 1))

0

Solution steps

x \to 0 + lim (ln (x + 1))

Plug in the value

x = 0

= ln (0 + 1)

Simplify

ln (0 + 1) : 0

= 0

y y^{^{'}} = x

(0, 6), (3, - 24)

\int \frac{- e ^{2 x}}{1 + e ^{x}} d x

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\int (e^{2 y} - y cos (x) y) d x

What is the limit as x approaches 0+of ln(x+1) ?
The limit as x approaches 0+of ln(x+1) is 0