What is the derivative of f(x)=ln(cos(x)) ?

The derivative of f(x)=ln(cos(x)) is -tan(x)

What is the first derivative of f(x)=ln(cos(x)) ?

The first derivative of f(x)=ln(cos(x)) is -tan(x)

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derivative of

f (x) = ln (cos (x))

- tan (x)

Solution steps

\frac{d}{d x} (ln (cos (x)))

Apply the chain rule:

\frac{1}{cos ( x )} \frac{d}{d x} (cos (x))

= \frac{1}{cos ( x )} \frac{d}{d x} (cos (x))

\frac{d}{d x} (cos (x)) = - sin (x)

= \frac{1}{cos ( x )} (- sin (x))

Simplify

\frac{1}{cos ( x )} (- sin (x)) : - tan (x)

= - tan (x)

\frac{d}{d x} (ln (x^{2} + 2))

n = 1 \sum \infty (x + 1)^{n}

x \to - \infty lim (- 18 x^{4})

\int \frac{1}{( ( a x ) ^{2} - b ^{2} ) ^{\frac{3}{2}}} d x

\int x + 20 d x

What is the derivative of f(x)=ln(cos(x)) ?
The derivative of f(x)=ln(cos(x)) is -tan(x)
What is the first derivative of f(x)=ln(cos(x)) ?
The first derivative of f(x)=ln(cos(x)) is -tan(x)