What is the derivative of arcsec(3x) ?

The derivative of arcsec(3x) is 1/(sqrt(x^2)\sqrt{9x^2-1)}

What is the first derivative of arcsec(3x) ?

The first derivative of arcsec(3x) is 1/(sqrt(x^2)\sqrt{9x^2-1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

arcsec (3 x)

\frac{1}{x ^{2} 9 x ^{2} - 1}

Solution steps

\frac{d}{d x} (arcsec (3 x))

Apply the chain rule:

\frac{1}{( 3 x ) ^{2} ( 3 x ) ^{2} - 1} \frac{d}{d x} (3 x)

= \frac{1}{( 3 x ) ^{2} ( 3 x ) ^{2} - 1} \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= \frac{1}{( 3 x ) ^{2} ( 3 x ) ^{2} - 1} \cdot 3

Simplify

\frac{1}{( 3 x ) ^{2} ( 3 x ) ^{2} - 1} \cdot 3 : \frac{1}{x ^{2} 9 x ^{2} - 1}

= \frac{1}{x ^{2} 9 x ^{2} - 1}

y^{^{'}} = x^{2} y

4 t h \frac{1}{x - 5}

\frac{8 x ^{2} + 4 x + 2}{x}

f (x) = - 3 x x + 1

\int \frac{2 + 2 x}{x - 4 x ( 1 + x )} d x

What is the derivative of arcsec(3x) ?
The derivative of arcsec(3x) is 1/(sqrt(x^2)\sqrt{9x^2-1)}
What is the first derivative of arcsec(3x) ?
The first derivative of arcsec(3x) is 1/(sqrt(x^2)\sqrt{9x^2-1)}