What is the integral of e^{x^5}x^4 ?

The integral of e^{x^5}x^4 is 1/5 e^{x^5}+C

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integral of e^{x^5}x^4

\int e^{x^{5}} x^{4} d x

\frac{1}{5} e^{x^{5}} + C

Solution steps

\int e^{x^{5}} x^{4} d x

Apply u-substitution

: \int \frac{e ^{u}}{5} d u

= \int \frac{e ^{u}}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{5} e^{u}

Substitute back

u = x^{5}

= \frac{1}{5} e^{x^{5}}

Add a constant to the solution

= \frac{1}{5} e^{x^{5}} + C

\frac{d}{d x} (\frac{x - 5}{x ^{2} - 3 x + 15})

x \to 2 lim (\frac{e ^{x}}{x ^{3}})

n = 0 \sum \infty \frac{1}{4}^{2}

\int - \frac{x}{1 + x ^{4}} d x

y^{^{'}} = \frac{3}{3 y}

What is the integral of e^{x^5}x^4 ?
The integral of e^{x^5}x^4 is 1/5 e^{x^5}+C