What is (\partial)/(\partial x)(tan(2x-y)) ?

The answer to (\partial)/(\partial x)(tan(2x-y)) is sec^2(2x-y)*2

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(\partial)/(\partial x)(tan(2x-y))

\frac{\partial}{\partial x} (tan (2 x - y))

sec^{2} (2 x - y) \cdot 2

Solution steps

\frac{\partial}{\partial x} (tan (2 x - y))

Treat

y

as a constant

Apply the chain rule:

sec^{2} (2 x - y) \frac{\partial}{\partial x} (2 x - y)

= sec^{2} (2 x - y) \frac{\partial}{\partial x} (2 x - y)

\frac{\partial}{\partial x} (2 x - y) = 2

= sec^{2} (2 x - y) \cdot 2

\frac{\partial}{\partial x} ((x^{2} - 2) e^{x^{2} y})

\int \frac{30}{30 + e ^{x}} d x

y = 4 (6 - x^{2})^{5}

\int 4 m (9 m^{2} - 10 m) d m

ln (15 x)

What is (\partial)/(\partial x)(tan(2x-y)) ?
The answer to (\partial)/(\partial x)(tan(2x-y)) is sec^2(2x-y)*2