What is the derivative of p(t)=5e^{0.0278t} ?

The derivative of p(t)=5e^{0.0278t} is 0.139e^{0.0278t}

What is the first derivative of p(t)=5e^{0.0278t} ?

The first derivative of p(t)=5e^{0.0278t} is 0.139e^{0.0278t}

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derivative of

p (t) = 5 e^{0.0278 t}

0.139 e^{0.0278 t}

Solution steps

\frac{d}{d t} (5 e^{0.0278 t})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d t} (e^{0.0278 t})

Apply the chain rule:

e^{0.0278 t} \frac{d}{d t} (0.0278 t)

= e^{0.0278 t} \frac{d}{d t} (0.0278 t)

\frac{d}{d t} (0.0278 t) = 0.0278

= 5 e^{0.0278 t} \cdot 0.0278

Simplify

= 0.139 e^{0.0278 t}

\frac{d}{d x} (\frac{1}{2} x^{2} + 1)

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\int 2 e^{x} - 1 d x

\int 4 x + 1 d x

What is the derivative of p(t)=5e^{0.0278t} ?
The derivative of p(t)=5e^{0.0278t} is 0.139e^{0.0278t}
What is the first derivative of p(t)=5e^{0.0278t} ?
The first derivative of p(t)=5e^{0.0278t} is 0.139e^{0.0278t}