What is (\partial)/(\partial x)(2cos(x)cos(y)) ?

The answer to (\partial)/(\partial x)(2cos(x)cos(y)) is -2sin(x)cos(y)

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(\partial)/(\partial x)(2cos(x)cos(y))

\frac{\partial}{\partial x} (2 cos (x) cos (y))

- 2 sin (x) cos (y)

Solution steps

\frac{\partial}{\partial x} (2 cos (x) cos (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 cos (y) \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= 2 cos (y) (- sin (x))

Simplify

= - 2 sin (x) cos (y)

h \to 0 lim (\frac{13 h}{h})

x \to 2 lim (2 x^{2} - 7 x - 15)

\frac{\partial}{\partial x} (cos (π x y))

\int 4 e^{- 2 x} sin (2 x) d x

x \to 1 lim (x (3))

What is (\partial)/(\partial x)(2cos(x)cos(y)) ?
The answer to (\partial)/(\partial x)(2cos(x)cos(y)) is -2sin(x)cos(y)