What is the solution for (dy)/(dx)=((x-3))/(2-y) ?

The solution for (dy)/(dx)=((x-3))/(2-y) is y=2-sqrt(-x^2+6x+4-c_{1)},y=sqrt(-x^2+6x+4-c_{1)}+2

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(dy)/(dx)=((x-3))/(2-y)

\frac{d y}{d x} = \frac{( x - 3 )}{2 - y}

y = 2 - - x^{2} + 6 x + 4 - c_{1}, y = - x^{2} + 6 x + 4 - c_{1} + 2

Solution steps

\frac{d y}{d x} = \frac{( x - 3 )}{2 - y}

Solve separable ODE:

y = 2 - - x^{2} + 6 x + 4 - c_{1}, y = - x^{2} + 6 x + 4 - c_{1} + 2

y = 2 - - x^{2} + 6 x + 4 - c_{1}, y = - x^{2} + 6 x + 4 - c_{1} + 2

\frac{d}{d x} (- x^{2})

\frac{d}{d x} (sec^{2} (x) tan (x))

\frac{\partial}{\partial x} (ln (x + 7 y + 2 z))

\int_{6}^{8} \frac{72}{( x - 6 ) ^{3}} d x

x \to 3 lim (f (x))

What is the solution for (dy)/(dx)=((x-3))/(2-y) ?
The solution for (dy)/(dx)=((x-3))/(2-y) is y=2-sqrt(-x^2+6x+4-c_{1)},y=sqrt(-x^2+6x+4-c_{1)}+2