What is the tangent of 3.5x-2x^2 ?

The tangent of 3.5x-2x^2 is y=(3.5-4a_{0})x+2a_{0}^2

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tangent of 3.5x-2x^2

tangent of

3.5 x - 2 x^{2}

y = (3.5 - 4 a_{0}) x + 2 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 3.5 a_{0} - 2 a_{0}^{2})

Find the slope of

y = 3.5 x - 2 x^{2} : \frac{d y}{d x} = 3.5 - 4 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3.5 - 4 a_{0}

Find the line with slope m=

3.5 - 4 a_{0}

and passing through

(a_{0}, 3.5 a_{0} - 2 a_{0}^{2}) : y = (3.5 - 4 a_{0}) x + 2 a_{0}^{2}

y = (3.5 - 4 a_{0}) x + 2 a_{0}^{2}

\int \frac{1 - 2 x}{x + 1} d x

\frac{d}{d r} (e^{r} + r^{e})

\int cot (24 x) d x

13 sin (x), 13 cos (x), 0, π

x \to \infty lim ([0, x])

What is the tangent of 3.5x-2x^2 ?
The tangent of 3.5x-2x^2 is y=(3.5-4a_{0})x+2a_{0}^2