What is the derivative of 2sin(t)*cos(t) ?

The derivative of 2sin(t)*cos(t) is cos(2t)*2

What is the first derivative of 2sin(t)*cos(t) ?

The first derivative of 2sin(t)*cos(t) is cos(2t)*2

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derivative of

2 sin (t) \cdot cos (t)

cos (2 t) \cdot 2

Solution steps

\frac{d}{d t} (2 sin (t) cos (t))

Simplify

2 sin (t) cos (t) : sin (2 t)

= \frac{d}{d t} (sin (2 t))

Apply the chain rule:

cos (2 t) \frac{d}{d t} (2 t)

= cos (2 t) \frac{d}{d t} (2 t)

\frac{d}{d t} (2 t) = 2

= cos (2 t) \cdot 2

y^{^{'}} = (x + y - 4)^{2}

x \to 1 lim (cos (π \cdot x))

\int_{2}^{\infty} x e^{- x^{2}} d x

\frac{d}{d x} (4 - x)

\int \frac{sinh ( x )}{1 + cosh ( x )} d x

What is the derivative of 2sin(t)*cos(t) ?
The derivative of 2sin(t)*cos(t) is cos(2t)*2
What is the first derivative of 2sin(t)*cos(t) ?
The first derivative of 2sin(t)*cos(t) is cos(2t)*2