What is the derivative of x+3y^{1/3} ?

The derivative of x+3y^{1/3} is 1+(\frac{dy)/(dx)}{y^{2/3}}

What is the first derivative of x+3y^{1/3} ?

The first derivative of x+3y^{1/3} is 1+(\frac{dy)/(dx)}{y^{2/3}}

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\frac{d}{d x} (x + 3 y^{\frac{1}{3}})

1 + \frac{\frac{d y}{d x}}{y ^{\frac{2}{3}}}

Solution steps

\frac{d}{d x} (x + 3 y^{\frac{1}{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (3 y^{\frac{1}{3}})

\frac{d x}{d x} = 1

\frac{d}{d x} (3 y^{\frac{1}{3}}) = \frac{\frac{d y}{d x}}{y ^{\frac{2}{3}}}

= 1 + \frac{\frac{d y}{d x}}{y ^{\frac{2}{3}}}

y = \frac{x ^{3}}{x - 1}

\frac{\partial}{\partial x} (y e^{x} + sin (y))

\frac{\partial}{\partial x} (y ln (x^{2} + y^{2} + 5) - 7)

\int \frac{- 1}{x - 2} d x

\int 4 x^{3} + e^{x} + 1 d x

What is the derivative of x+3y^{1/3} ?
The derivative of x+3y^{1/3} is 1+(\frac{dy)/(dx)}{y^{2/3}}
What is the first derivative of x+3y^{1/3} ?
The first derivative of x+3y^{1/3} is 1+(\frac{dy)/(dx)}{y^{2/3}}