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Popular >

(1-x)y^'=y^2

Solution

(1 - x) y^{^{'}} = y^{2}

Solution

y = - \frac{1}{- ln ( 1 - x ) + c _{1}}

Solution steps

(1 - x) y^{'} (x) = y^{2}

Solve separable ODE:

y = - \frac{1}{- ln ( 1 - x ) + c _{1}}

y = - \frac{1}{- ln ( 1 - x ) + c _{1}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for (1-x)y^'=y^2 ?
The solution for (1-x)y^'=y^2 is y=-1/(-ln(1-x)+c_{1)}