What is the integral of (piy^4)/(16) ?

The integral of (piy^4)/(16) is (piy^5)/(80)+C

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integral of (piy^4)/(16)

\int \frac{π y ^{4}}{16} d y

\frac{π y ^{5}}{80} + C

Solution steps

\int \frac{π y ^{4}}{16} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{π}{16} \cdot \int y^{4} d y

Apply the Power Rule

: \frac{y ^{5}}{5}

= \frac{π}{16} \cdot \frac{y ^{5}}{5}

Simplify

\frac{π}{16} \cdot \frac{y ^{5}}{5} : \frac{π y ^{5}}{80}

= \frac{π y ^{5}}{80}

Add a constant to the solution

= \frac{π y ^{5}}{80} + C

f (x) = - 2 cos (x)

\frac{\partial}{\partial x} (x^{3} - 5 x^{2} + y^{3} - 8 y)

\int (1 - \frac{5}{y} + x) d y

y = (4 e)^{x}

\frac{d}{d x} (\frac{1 - 5 x ^{2}}{3 3 + 2 x})

What is the integral of (piy^4)/(16) ?
The integral of (piy^4)/(16) is (piy^5)/(80)+C