What is the solution for x^4(dy)/(dx)+2x^3y=1 ?

The solution for x^4(dy)/(dx)+2x^3y=1 is y=-1/(x^3)+(c_{1})/(x^2)

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x^4(dy)/(dx)+2x^3y=1

x^{4} \frac{d y}{d x} + 2 x^{3} y = 1

y = - \frac{1}{x ^{3}} + \frac{c _{1}}{x ^{2}}

Solution steps

x^{4} \frac{d y}{d x} + 2 x^{3} y = 1

Solve linear ODE:

y = - \frac{1}{x ^{3}} + \frac{c _{1}}{x ^{2}}

y = - \frac{1}{x ^{3}} + \frac{c _{1}}{x ^{2}}

\frac{d}{d x} (\frac{1}{4 - x})

f (x) = \frac{sin ( x ) - x}{x ^{2}}

\int \frac{x}{4 - x ^{2}} d x

\frac{\partial}{\partial x} (11 x^{2} - 2 x^{3})

\int_{0}^{1} 2 π (x) (9 - 8 x - x^{2}) d x

What is the solution for x^4(dy)/(dx)+2x^3y=1 ?
The solution for x^4(dy)/(dx)+2x^3y=1 is y=-1/(x^3)+(c_{1})/(x^2)