What is the limit as x approaches 1+of sqrt(2x-2)-2 ?

The limit as x approaches 1+of sqrt(2x-2)-2 is -2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 1+of sqrt(2x-2)-2

x \to 1 + lim (2 x - 2 - 2)

- 2

Solution steps

x \to 1 + lim (2 x - 2 - 2)

Plug in the value

x = 1

= 2 \cdot 1 - 2 - 2

Simplify

= - 2

\int \frac{6 x + 5}{3 x ^{2} + 5 x} d x

\int_{3}^{5} \frac{1}{x ^{2} - 9} d x

f (x) = (x^{3} - 10 x) (3 x^{2} + 4 x)

y = x^{2} ln (x), y = 4 ln (x)

\frac{d}{d x} ((e^{2 x}) 3 x^{3} + 1)

What is the limit as x approaches 1+of sqrt(2x-2)-2 ?
The limit as x approaches 1+of sqrt(2x-2)-2 is -2