What is the integral from-8 to 8 of (4x^9+7x^5) ?

The integral from-8 to 8 of (4x^9+7x^5) is 0

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integral from-8 to 8 of (4x^9+7x^5)

\int_{- 8}^{8} (4 x^{9} + 7 x^{5}) d x

0

Solution steps

\int_{- 8}^{8} 4 x^{9} + 7 x^{5} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

4 x^{9} + 7 x^{5} :

Odd

= 0

y = \frac{( x + 5 ) ^{5}}{7 x - 5}

\int_{0}^{6} 2 π x (6 x - x^{2}) d x

\frac{d}{d x} (cos^{2} (x) - cos (x))

\frac{d}{d x} (m (m - 1) x^{m - 2})

\frac{d}{d x} (arctan (1))

What is the integral from-8 to 8 of (4x^9+7x^5) ?
The integral from-8 to 8 of (4x^9+7x^5) is 0