What is the derivative of sqrt(2t^2-t) ?

The derivative of sqrt(2t^2-t) is (4t-1)/(2sqrt(2t^2-t))

What is the first derivative of sqrt(2t^2-t) ?

The first derivative of sqrt(2t^2-t) is (4t-1)/(2sqrt(2t^2-t))

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derivative of

2 t^{2} - t

\frac{4 t - 1}{2 2 t ^{2} - t}

Solution steps

\frac{d}{d t} (2 t^{2} - t)

Apply the chain rule:

\frac{1}{2 2 t ^{2} - t} \frac{d}{d t} (2 t^{2} - t)

= \frac{1}{2 2 t ^{2} - t} \frac{d}{d t} (2 t^{2} - t)

\frac{d}{d t} (2 t^{2} - t) = 4 t - 1

= \frac{1}{2 2 t ^{2} - t} (4 t - 1)

Simplify

\frac{1}{2 2 t ^{2} - t} (4 t - 1) : \frac{4 t - 1}{2 2 t ^{2} - t}

= \frac{4 t - 1}{2 2 t ^{2} - t}

\frac{d}{d x} (x - in x)

t e^{- 0.003 t} cos (10 t)

\int_{0}^{1} \frac{1}{( x + 1 ) ( x ^{2} + 1 )} d x

f (x) = x^{4} + 8 x^{3} + 2 x + 2, at x = 1

\frac{\partial}{\partial x} (\frac{12 x}{x + y})

What is the derivative of sqrt(2t^2-t) ?
The derivative of sqrt(2t^2-t) is (4t-1)/(2sqrt(2t^2-t))
What is the first derivative of sqrt(2t^2-t) ?
The first derivative of sqrt(2t^2-t) is (4t-1)/(2sqrt(2t^2-t))