What is the integral of (-0.5x+450) ?

The integral of (-0.5x+450) is -0.25x^2+450x+C

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integral of (-0.5x+450)

\int (- 0.5 x + 450) d x

- 0.25 x^{2} + 450 x + C

Solution steps

\int - 0.5 x + 450 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 0.5 x d x + \int 450 d x

\int 0.5 x d x = 0.25 x^{2}

\int 450 d x = 450 x

= - 0.25 x^{2} + 450 x

Add a constant to the solution

= - 0.25 x^{2} + 450 x + C

\frac{d y}{d x} = 4 x - 5

x \to 0 lim ((x)^{t a n (x)})

\frac{\partial}{\partial x} (\frac{y}{x ^{2} + y ^{2} + z ^{2}})

y = 7 x + 1, (5, 6)

\frac{\partial}{\partial x} (x y e^{x - 2 z})

What is the integral of (-0.5x+450) ?
The integral of (-0.5x+450) is -0.25x^2+450x+C