What is the derivative of 2sin(t) ?

The derivative of 2sin(t) is 2cos(t)

What is the first derivative of 2sin(t) ?

The first derivative of 2sin(t) is 2cos(t)

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derivative of

2 sin (t)

2 cos (t)

Solution steps

\frac{d}{d t} (2 sin (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (sin (t))

Apply the common derivative:

\frac{d}{d t} (sin (t)) = cos (t)

= 2 cos (t)

\frac{\partial}{\partial x} (y e^{(\frac{x}{y})})

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2} - 4 x}{x + 1})

\frac{d}{d x} (3 x^{2} 5 x + 3)

f (x) = 2 - 10 x, at x = - 1

\int (7 x) d x

What is the derivative of 2sin(t) ?
The derivative of 2sin(t) is 2cos(t)
What is the first derivative of 2sin(t) ?
The first derivative of 2sin(t) is 2cos(t)